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6x^2+38x+60=0
a = 6; b = 38; c = +60;
Δ = b2-4ac
Δ = 382-4·6·60
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(38)-2}{2*6}=\frac{-40}{12} =-3+1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(38)+2}{2*6}=\frac{-36}{12} =-3 $
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